Entry Exam Category: High School Equivalency Exams
Course: HiSET
Exam: HiSET Math Practice Test
Practice Question
The volume of 1 cup of water is 14.4 cubic inches. The diameter of an empty cylindrical can is 3.0 inches. The can holds 2.0 cups of water. What is the height of the can, to the nearest 0.1 inch?
Answer Choices
- A: 1
- B: 2
- C: 3.1
- D: 4.1
- E: 6.2
Correct Answer: D
Rationale: Volume of can = 2 × 14.4 = 28.8 cubic inches. Radius = 3/2 = 1.5 inches. Volume of cylinder = πr²h. So, 28.8 ≈ 3.1416 × (1.5)² × h = 3.1416 × 2.25 × h ≈ 7.0686h. Thus, h ≈ 28.8/7.0686 ≈ 4.074. To nearest 0.1 inch, h = 4.1. Options: 1.0, 2.0, 3.1, 6.2 incorrect; 4.1 correct.